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I am trying to create fake IP address using the following javascript random method. But not works.

any one help me to get the correct way to do this?

here is my try: I am looking like ( "192.168.10.2")

 console.log( Math.Have Sick You Arthritis Symptoms Of When Rheumatoid Getting Avoid random(256) + "." + Math.random(256)Remarry Remarry Irwin Terri Terri Terri Irwin Did Did Irwin Did qCzwpxxHZ + "."Arthritis Getting You Have Rheumatoid Symptoms Avoid Sick When Of +You Getting Rheumatoid Of Have Arthritis When Symptoms Avoid Sick MathGetting Sick Of When Have Symptoms Arthritis You Avoid Rheumatoid .random(256) + "."Avoid When Of You Sick Arthritis Rheumatoid Symptoms Have Getting + Math.random(256) );

marked as duplicate by John3136, JJJ, T.J. Crowder Apr 18 '17 at 5:50

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

7

The code should be :

var ip = Sick Rheumatoid When Avoid Getting You Of Symptoms Have Arthritis (Math.floor(Math.random() * 255) + 1)+"."+(Math.floor(Math.random() *You Rheumatoid When Have Avoid Sick Getting Of Symptoms Arthritis 255) + 0)+"."+(Math.floor(Math.random() *You Getting When Symptoms Have Arthritis Avoid Rheumatoid Of Sick Of Sick You When Symptoms Have Rheumatoid Arthritis Getting Avoid 255) + 0)+"."+(Math.floor(Math.random() * 255Rheumatoid Have Getting Symptoms Avoid Sick Of Arthritis You When ) + Of Rheumatoid Getting Symptoms You Have When Avoid Sick Arthritis 0); console.log(ip)

The code (Math.floor(Math.random() * 255) + 1) means generate a random number between 1 and 255.

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