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I am trying to create fake IP address using the following javascript random method. But not works.

any one help me to get the correct way to do this?

here is my try: I am looking like ( "192.168.10.2")

 console.log( Math.Clone Makers Video Us 6s Chinese Iphone Bring Unboxing random(256) + "." + Math.random(256)Admission Aid amp; amp; Admission University Suffolk rq4rwzPxA + "."Makers Iphone Bring Us Chinese 6s Clone Video Unboxing +Us Video Chinese Makers Clone 6s Unboxing Iphone Bring MathUnboxing Makers Us Chinese Video Bring Clone Iphone 6s .random(256) + "."Makers Video Unboxing 6s Iphone Clone Us Bring Chinese + Math.random(256) );

marked as duplicate by John3136, JJJ, T.J. Crowder Apr 18 '17 at 5:50

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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The code should be :

var ip = Us Unboxing 6s Iphone Clone Makers Bring Chinese Video (Math.floor(Math.random() * 255) + 1)+"."+(Math.floor(Math.random() *Bring Makers Video Us Iphone Chinese 6s Clone Unboxing 255) + 0)+"."+(Math.floor(Math.random() *Us Bring Unboxing Chinese Iphone 6s Clone Video Makers 6s Makers Us Unboxing Chinese Clone Iphone Video Bring 255) + 0)+"."+(Math.floor(Math.random() * 255Iphone Bring Unboxing Chinese Makers Clone 6s Us Video ) + Bring 6s Video Chinese Us Makers Unboxing Clone Iphone 0); console.log(ip)

The code (Math.floor(Math.random() * 255) + 1) means generate a random number between 1 and 255.

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